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222-9+11+12:2*14+14 = ? ( )

Hóa học Lớp 8: Lập các PTPU sau 1) MgCl2 + KOH → Mg(OH)2 + KCl 2) Cu(OH)2 + HCl → CuCl2 + H2O 3) Cu(OH)2 + H2SO4 → CuSO4 + H2O 4) P + O2 → P2O5 5) N2

Hóa học Lớp 8: Lập các PTPU sau
1) MgCl2 + KOH → Mg(OH)2 + KCl
2) Cu(OH)2 + HCl → CuCl2 + H2O
3) Cu(OH)2 + H2SO4 → CuSO4 + H2O
4) P + O2 → P2O5
5) N2 + O2 → NO
6) NO + O2 → NO2
7) NO2 + O2 + H2O → HNO3
8) K + O2 → K2O
9) Al + O2 → Al2 O3
10) Mg + HCl → MgCl2 + H2
11) Fe(OH)3→ Fe2O3 + H2O
12) Al2(SO4)3 + BaCl2 ——-→ BaSO4 + AlCl3, giúp em giải bài hóa này ạ, em cảm ơn thầy cô và các bạn nhiều.

Comments ( 2 )

  1. 1) $MgCl_2$+2KOH→$Mg(OH)_2$+2KCl
    2) $Cu(OH)_2$+2HCl→$CuCl_2$+$2H_2O$
    3) $Cu(OH)_2$+$H_2$$SO_4$→$CuSO_4$+$2H_2O$
    4) 4P+$5O_2$$\xrightarrow[]{t^o}$$2P_2$$O_5$
    5) $N_2$+$O_2$$\xrightarrow[]{t^o}$2NO
    6) 2NO+$O_2$$\xrightarrow[]{t^o}$$2NO_2$
    7) $4NO_2$+$O_2$+$2H_2O$→$4HNO_3$
    8) 4K+$O_2$$\xrightarrow[]{t^o}$$2K_2O$
    9) 4Al+$3O_2$$\xrightarrow[]{t^o}$$2Al_2$$O_3$
    10) Mg+2HCl→$MgCl_2$+$H_2$
    11) $2Fe(OH)_3$$\xrightarrow[]{t^o}$$Fe_2$$O_3$+$3H_2O$
    12) $Al_2(SO$$_4)$$_3$+$3BaCl_2$→$3BaSO_4↓$+$2AlCl_3$
     

  2. 1/ MgCl2 + 2KOH → Mg(OH)2 + 2KCl
    2/ Cu(OH)2 + 2 HCl → CuCl2 + 2H2O
    3/ Cu(OH)2 + H2SO4 → CuSO4 + 2H2O
    4/ 4P + 5O2 → 2P2O5
    5/ N2 + O2 → 2NO
    6/ 2NO + O2 → 2NO2
    7/ 4NO2 + O2 + 2H2O → 4HNO3
    8/ 4K + O2 → 2K2O
    9/ 4Al + 3O2 → 2Al2O3
    10/ Mg + 2HCl → MgCl2 + H2
    11/ 2Fe(OH)3 → Fe2O3 + 3H2O
    12/ Al2(SO4)3 + 3BaCl2 → 3BaSO4 + 2AlCl3

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222-9+11+12:2*14+14 = ? ( )