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222-9+11+12:2*14+14 = ? ( )

Hóa học Lớp 10: MNO2_ Cl2_ HCl _FeCl2_ FeCl3 _fe(oh)3 _ Fe2 O3

Hóa học Lớp 10: MNO2_ Cl2_ HCl _FeCl2_ FeCl3 _fe(oh)3 _
Fe2 O3, giúp em giải bài hóa này ạ, em cảm ơn thầy cô và các bạn nhiều.

Comments ( 2 )

  1. $\text{PTHH:}$
    $\text{MnO$_{2}$+4HCl$\xrightarrow[]{t^o}$MnCl$_{2}$+Cl$_{2}$+2H$_{2}$O}$
    $\text{Cl$_{2}$+H$_{2}$$\xrightarrow[]{ánh sáng}$2HCl}$
    $\text{Fe+2HCl→FeCl$_{2}$+H$_{2}$}$
    $\text{2FeCl$_{2}$+Cl$_{2}$$\xrightarrow[]{t^o}$2FeCl$_{3}$}$
    $\text{FeCl$_{3}$+3NaOH→Fe(OH)$_{3}$+3NaCl}$
    $\text{2Fe(OH)$_{3}$$\xrightarrow[]{t^o}$Fe$_{2}$O$_{3}$+3H$_{2}$O}$

  2. – MnO_2+4HCl→MnCl_2+Cl_2↑+2H_2O
    – H_2+Cl_2 $\xrightarrow[]{t^o}$ 2HCl
    – Fe+2HCl→FeCl_2+H_2
    – 2FeCl_2+Cl_2 $\xrightarrow[]{t^o}$ 2FeCl_3
    – FeCl_3+3NaOH→Fe(OH)_3↓+3NaCl
    – 2Fe(OH)_3 $\xrightarrow[]{t^o}$ Fe_2O_3+3H_2O

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222-9+11+12:2*14+14 = ? ( )