Toán Lớp 9: Tìm x biết $\sqrt[3]{x}$ = -2
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Toán Lớp 9: Tìm x biết $\sqrt[3]{x}$ = -2
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\sqrt[3]{x} = -2
⇔ ($\sqrt[3]{x}$ )^3 = (-2)^3
⇔ x = -8
vậy x=-8
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