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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: (-1/7)^0+(-1/7)^1+(-1/7)^2+…+(-1/7)^2017

Toán Lớp 7: (-1/7)^0+(-1/7)^1+(-1/7)^2+…+(-1/7)^2017

Comments ( 2 )

  1. $\text{#Táo vàng}$
    $\text{Đặt}$ (-1/7)^{0} + (-1/7)^{1} + … + (-1/7)^{2017} $\text{là S}$
    => S = (-1/7)^{0} + (-1/7)^{1} + … + (-1/7)^{2017}
    => -1/7 . S = -1/7 . [(-1/7)^{0} + (-1/7)^{1} + … + (-1/7)^{2017}]
    => -1/7 . S = (-1/7)^{1} + (-1/7)^{2} + … + (-1/7)^{2018}
    => S – {-1}/7 . S = [(-1/7)^{0} + (-1/7)^{1} + … + (-1/7)^{2017}] – [(-1/7)^{1} + (-1/7)^{2} + … + (-1/7)^{2018})
    => 8/7 . S = 1 – 1/7^{2018}
    => S = (1 – 1/7^{2018}) : 8/7
    $\text{Vậy}$ S = (1 – 1/7^{2018}) : 8/7

  2. Giải đáp:
    $\begin{array}{l}
    A = {\left( { – \dfrac{1}{7}} \right)^0} + {\left( { – \dfrac{1}{7}} \right)^1} + {\left( { – \dfrac{1}{7}} \right)^2} + … + {\left( { – \dfrac{1}{7}} \right)^{2017}}\\
     \Leftrightarrow  – \dfrac{1}{7}.A = {\left( { – \dfrac{1}{7}} \right)^1} + {\left( { – \dfrac{1}{7}} \right)^2} + {\left( { – \dfrac{1}{7}} \right)^3} + … + {\left( { – \dfrac{1}{7}} \right)^{2018}}\\
     \Leftrightarrow A – \left( {\dfrac{{ – 1}}{7}A} \right) = {\left( { – \dfrac{1}{7}} \right)^0} – {\left( { – \dfrac{1}{7}} \right)^{2018}}\\
     \Leftrightarrow \dfrac{8}{7}A = 1 – \dfrac{1}{{{7^{2018}}}}\\
     \Leftrightarrow A = \dfrac{7}{8}.\dfrac{1}{{{{8.7}^{2017}}}}
    \end{array}$

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222-9+11+12:2*14+14 = ? ( )