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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tìm số nguyên x biết : (x-4).(x+1) < 0

Toán Lớp 7: Tìm số nguyên x biết : (x-4).(x+1) < 0

Comments ( 2 )

  1. ~ Bạn tham khảo ~
    (x-4) .(x+1) < 0
    => x-4 ; x+1 là hai số nguyên khác dấu
    So sánh : x -4 ; x+1
    x = x ; -4 < +1
    => x – 4 < x + 1
    => x -4 < 0
    => x < 4
    => x + 1 >0
    => x > -1
    => -1 < x < 4
    => x = { 0 ; 1; 2;3 }
    Vậy x = { 0;1;2;3}
    $#Vịt vàng$

  2. (x-4)(x+1)<0(x inZZ)
    <=>[({(x-4<0),(x+1>0):}),({(x-4>0),(x+1<0):}):}
    <=>[({(x<4),(x> -1):}(TM)),({(x>4),(x<-1):}(L)):}
    Vậy x in{0; 1; 2; 3}
    \text{#Familyisnumber1}

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222-9+11+12:2*14+14 = ? ( )

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