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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x a. x(x-2)+x-2=0 b. 2(x+3)-x^2-3x=0 c. x^3+x^2+x+1=0 d. 2x^3-3x^2+4x-6=0 e. 2x(3x-5)=10-6x

Home/ Toán Lớp 8: Tìm x a. x(x-2)+x-2=0 b. 2(x+3)-x^2-3x=0 c. x^3+x^2+x+1=0 d. 2x^3-3x^2+4x-6=0 e. 2x(3x-5)=10-6x

Toán Lớp 8: Tìm x a. x(x-2)+x-2=0 b. 2(x+3)-x^2-3x=0 c. x^3+x^2+x+1=0 d. 2x^3-3x^2+4x-6=0 e. 2x(3x-5)=10-6x

Tháng Sáu 29, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: Tìm x
a. x(x-2)+x-2=0
b. 2(x+3)-x^2-3x=0
c. x^3+x^2+x+1=0
d. 2x^3-3x^2+4x-6=0
e. 2x(3x-5)=10-6x

Comments ( 2 )

  1. thanhthuythu
    thanhthuythu
    29 Tháng Sáu, 2022 at 1:13 sáng
    Reply
    Giải đáp + giải thích :
     

    toan-lop-8-tim-a-2-2-0-b-2-3-2-3-0-c-3-2-1-0-d-2-3-3-2-4-6-0-e-2-3-5-10-6

  2. behocgioitoan
    behocgioitoan
    29 Tháng Sáu, 2022 at 1:13 sáng
    Reply
    $a)x(x-2)+x-2=0$ $⇔(x-2)(x+1)=0$ ⇔\(\left[ \begin{array}{l}x=2\\x=-1\end{array} \right.\)
    $b)2(x+3)-x^2-3x=0$ $⇔2x+6-x^2-3x=0$ $⇔-x^2-x+6=0$ ⇔ \(\left[ \begin{array}{l}x=2\\x=-3\end{array} \right.\)
    $c)x^3+x^2+x+1=0$ $⇔x^2(x+1)+x+1=0$ $⇔(x+1)(x^2+1)=0$ $⇔\left[ \begin{array}{l}x+1=0⇔x=-1 \\x^2+1=0(VN)\end{array} \right.$
    $d)2x^3-3x^2+4x-6=0$ $⇔x^2(2x-3)+2(2x-3)=0$ $⇔(2x-3)(x^2+2)=0$ $⇔\left[ \begin{array}{l}x=3/2\\x^2=-2(VN)\end{array} \right.$
    $e)2x(3x-5)=10-6x$ $⇔6x^2-10x=10-6x$ $⇔6x^2-4x-10=0$ $⇔\left[ \begin{array}{l}x=5/3\\x=-1\end{array} \right.$
     

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222-9+11+12:2*14+14 = ? ( )

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