Toán Lớp 9: $\frac{a}{b} \sqrt{\frac{b}{a}}$ – $\frac{1}{a} \sqrt{a^3b} + \frac{2}{3b} \sqrt{9ab^3}$ với a, b > 0
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Toán Lớp 9: $\frac{a}{b} \sqrt{\frac{b}{a}}$ – $\frac{1}{a} \sqrt{a^3b} + \frac{2}{3b} \sqrt{9ab^3}$ với a, b > 0
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