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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: bài 1 Sin2x = 1/2 Bài 2 : √3 sinx + cosx = 1

Tháng Sáu 9, 2022 Toán học 2 Comments 0 views

Toán Lớp 11: bài 1
Sin2x = 1/2
Bài 2 : √3 sinx + cosx = 1

Comments ( 2 )

  1. huongtructram
    huongtructram
    9 Tháng Sáu, 2022 at 6:42 sáng
    Reply
    1.sin2x=1/2
    ⇔sin2x=sin(pi/6)
    $⇔$\(\left[ \begin{array}{l}2x=\dfrac{\pi}{6}+k2\pi\\2x=\pi-\dfrac{\pi}{6}+k2\pi\end{array} \right.\)
    $⇔$\(\left[ \begin{array}{l}x=\dfrac{\pi}{12}+k\pi\\x=\dfrac{5\pi}{12}+k\pi\end{array} \right.\) $(k∈Z)$
    2.sqrt[3]sinx+cosx=1
    ⇔sqrt[3]/2sinx+1/2cosx=1/2
    ⇔cos(pi/6)sinx+sin(pi/6)cosx=1/2
    ⇔sin(x+pi/6)=1/2
    ⇔sin(x+pi/6)=sin(pi/6)
    $⇔$\(\left[ \begin{array}{l}x+\dfrac{\pi}{6}=\dfrac{\pi}{6}+k2\pi\\x+\dfrac{\pi}{6}=\pi-\dfrac{\pi}{6}+k2\pi\end{array} \right.\)
    $⇔$\(\left[ \begin{array}{l}x=k2\pi\\x=\dfrac{2\pi}{3}+k2\pi\end{array} \right.\)$(k∈Z)$

  2. hoquyly
    hoquyly
    9 Tháng Sáu, 2022 at 6:41 sáng
    Reply

    Bài cuối bạn chuyển vế rồi ra đáp án nhe
    toan-lop-11-bai-1-sin2-1-2-bai-2-3-sin-cos-1

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222-9+11+12:2*14+14 = ? ( )

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