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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: tìm x biết a) 3x .(x-2)-x-2=0 b)x ² +x-6=0 c)x ²+4x+4=0

Toán Lớp 8: tìm x biết
a) 3x .(x-2)-x-2=0
b)x ² +x-6=0
c)x ²+4x+4=0

Comments ( 2 )

  1. Giải đáp:
    a) <=> S = {1/3; 2}
    b) <=> S = {2; 3}
    c) <=> S = {-2}
    Lời giải và giải thích chi tiết:
    a) 3x(x-2)-x+2=0
    <=> 3x^2 – 6x – x + 2 = 0
    <=> 3x^2 – 7x + 2 = 0
    <=> 3x^2 – x – 6x + 2
    <=> x(3x – 1) – 2(3x – 1) = 0
    <=> (3x – 1)(x – 2) = 0
    <=> $\left[\begin{matrix} 3x-1=0\\ x-2=0\end{matrix}\right.$
    <=> $\left[\begin{matrix} x=\dfrac{1}{3}\\ x = 2\end{matrix}\right.$
    <=> S = {1/3; 2}
    – – – – –
    b) x^2 + x – 6 = 0
    <=> x^2 – 2x + 3x – 6 = 0
    <=> x(x – 2) + 3(x – 2) = 0
    <=> (x – 2)(x + 3) = 0
    <=> $\left[\begin{matrix} x-2=0\\ x+3=0\end{matrix}\right.$
    <=> $\left[\begin{matrix} x=2\\ x=-3\end{matrix}\right.$
    <=> S = {2; 3}
    – – – – –
    c) x^2 + 4x + 4 = 0
    <=> (2 + x)^2 = 0
    <=> x + 2 = 0
    <=> x = -2
    <=> S = {-2}

  2. Giải đáp + Lời giải và giải thích chi tiết !
    to Tìm x:
    a)
    3x(x-2)-x+2 = 0
    <=> 3x(x-2)-(x-2) = 0
    <=> (3x-1)(x-2) = 0
    <=> \(\left[ \begin{array}{l}3x-1=0\\x-2=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}3x=1\\x=2\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=\dfrac{1}{3}\\x=2\end{array} \right.\) 
    Vậy S= {1/3; 2}
    b)
    x^2+x-6 = 0
    <=> x^2+3x-2x-6 = 0
    <=> (x^2+3x)-(2x+6) = 0
    <=> x(x+3)-2(x+3) = 0
    <=> (x-2)(x+3) = 0
    <=> \(\left[ \begin{array}{l}x-2=0\\x+3=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=2\\x=-3\end{array} \right.\) 
    Vậy S= {2; -3}
    c)
    x^2+4x+4 = 0
    <=> x^2+2. x. 2+2^2 = 0
    <=> (x+2)^2 = 0
    <=> x+2 = 0
    <=> x = -2
    Vậy S= {-2}
     

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222-9+11+12:2*14+14 = ? ( )