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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Bài 1 : 1. $\sqrt{4+2}$$\sqrt{3}$ – $\sqrt{3}$ 2. $\sqrt{7-4}$$\sqrt{3}$ + $\sqrt{3}$ Bài 2 : 1. ($\sqrt{18}$ + $\sqrt{32}$ – $\sqrt{

Home/ Toán Lớp 9: Bài 1 : 1. $\sqrt{4+2}$$\sqrt{3}$ – $\sqrt{3}$ 2. $\sqrt{7-4}$$\sqrt{3}$ + $\sqrt{3}$ Bài 2 : 1. ($\sqrt{18}$ + $\sqrt{32}$ – $\sqrt{

Toán Lớp 9: Bài 1 : 1. $\sqrt{4+2}$$\sqrt{3}$ – $\sqrt{3}$ 2. $\sqrt{7-4}$$\sqrt{3}$ + $\sqrt{3}$ Bài 2 : 1. ($\sqrt{18}$ + $\sqrt{32}$ – $\sqrt{

Tháng Năm 19, 2022 Toán học 1 Comment 0 views

Toán Lớp 9: Bài 1 :
1. $\sqrt{4+2}$$\sqrt{3}$ – $\sqrt{3}$
2. $\sqrt{7-4}$$\sqrt{3}$ + $\sqrt{3}$
Bài 2 :
1. ($\sqrt{18}$ + $\sqrt{32}$ – $\sqrt{50}$) nhân $\sqrt{2}$
2. $\sqrt{100}$ -$\sqrt{32}$ nhan $\sqrt{2}$ + $\sqrt{18}$ nhan $\sqrt{2}$
3. ($\sqrt{12}$ + 3$\sqrt{75}$ – 4$\sqrt{27}$) nhan $\sqrt{3}$

Comments ( 1 )

  1. bichquyenlien
    bichquyenlien
    19 Tháng Năm, 2022 at 4:06 chiều
    Reply
    Bài 1:
    Giải đáp:
     a) $\sqrt{4+2}$ .$\sqrt{3}$ – $\sqrt{3}$
    = $\sqrt{6}$ . $\sqrt{3}$ – $\sqrt{3}$
    = $\sqrt{6.3}$ – $\sqrt{3}$
    = $\sqrt{18}$ – $\sqrt{3}$
    = $3\sqrt{2}$ – $\sqrt{3}$
    b) $\sqrt{7-4}$ . $\sqrt{3}$ + $\sqrt{3}$
    = $\sqrt{3}$ . $\sqrt{3}$ + $\sqrt{3}$
    = 3 +$\sqrt{3}$
    Bài 2:
    Giải đáp:
    a) ( $\sqrt{9.2}$ + $\sqrt{16.2}$ – $\sqrt{25.2}$ )$\sqrt{2}$
    = ( $3\sqrt{2}$ + $4\sqrt{2}$ – $5\sqrt{2}$ )$\sqrt{2}$
    = 6 + 8 – 10
    = 4
    b) $\sqrt{100}$ – $\sqrt{32}$ . $\sqrt{2}$ + $\sqrt{18}$ . $\sqrt{2}$
    = 10 – $\sqrt{64}$ + $\sqrt{36}$
    = 10 – 8 + 6
    = 8
    c)( $\sqrt{12}$ +$3\sqrt{75}$ – $4\sqrt{27}$ )$\sqrt{3}$
    = ( $\sqrt{4.2}$ + $4\sqrt{25.3}$ – $4\sqrt{9.3}$ )$\sqrt{3}$
    = ($2\sqrt{3}$ + $15\sqrt{3}$ – $12\sqrt{3}$ )$\sqrt{3}$
    = 6 + 45 – 36
    = 15

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222-9+11+12:2*14+14 = ? ( )

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