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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x: 1/ x^2 – 4x = 0 2/ x^3 – 9x = 0 3/ 2x(x – 3) + 5(x – 3) = 0

Home/ Toán Lớp 8: Tìm x: 1/ x^2 – 4x = 0 2/ x^3 – 9x = 0 3/ 2x(x – 3) + 5(x – 3) = 0

Toán Lớp 8: Tìm x: 1/ x^2 – 4x = 0 2/ x^3 – 9x = 0 3/ 2x(x – 3) + 5(x – 3) = 0

Tháng Mười Một 19, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: Tìm x:
1/ x^2 – 4x = 0
2/ x^3 – 9x = 0
3/ 2x(x – 3) + 5(x – 3) = 0

Comments ( 2 )

  1. kymmailien
    kymmailien
    19 Tháng Mười Một, 2022 at 9:00 sáng
    Reply
    $\text{x²-4x=0}$
    $\text{⇔x(x-4)=0}$
    $\text{⇔\(\left[ \begin{array}{l}x=0\\x-4=0\end{array} \right.\)}$
    $\text{⇔\(\left[ \begin{array}{l}x=0\\x=4\end{array} \right.\) }$
    _______________________________
    $\text{x³-9x=0}$
    $\text{⇔x(x²-9)=0}$
    $\text{⇔x(x-3)(x+3)=0}$
    $\text{⇔\(\left[ \begin{array}{l}x=0\\x-3=0\\x+3=0\end{array} \right.\) }$
    $\text{⇔\(\left[ \begin{array}{l}x=0\\x=3\\x=-3\end{array} \right.\) }$
    _________________________________________________–
    $\text{2x(x-3)+5(x-3)=0}$
    $\text{⇔(x-3)(2x+5)=0}$
    $\text{⇔\(\left[ \begin{array}{l}x-3=0\\2x+5=0\end{array} \right.\) }$
    $\text{⇔\(\left[ \begin{array}{l}x=3\\x=-\dfrac{5}{2}\end{array} \right.\) }$
     

  2. hienthucthu97
    hienthucthu97
    19 Tháng Mười Một, 2022 at 9:00 sáng
    Reply
    1.  x^2 – 4x = 0
    <=>x(x – 4) = 0
    <=>\(\left[ \begin{array}{l}x=0\\x-4=0\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}x=0\\x=4\end{array} \right.\)
    2.  x^3 – 9x = 0
    <=>x(x^2 – 9) = 0
    <=>\(\left[ \begin{array}{l}x=0\\x^2-9=0\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}x=0\\x^2=9\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}x=0\\x=±3\end{array} \right.\)
    3.  2x(x – 3) + 5(x – 3) = 0
    <=>(2x + 5)(x – 3) = 0
    <=>\(\left[ \begin{array}{l}2x+5=0\\x-3=0\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}2x=-5\\x=3\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}x=-\frac{5}{2}\\x=3\end{array} \right.\)

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222-9+11+12:2*14+14 = ? ( )

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