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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: tìm x a, ( x+2)(x+3)-(x-2)(x-5)+6 b, 2x^2+x=0

Home/ Toán Lớp 8: tìm x a, ( x+2)(x+3)-(x-2)(x-5)+6 b, 2x^2+x=0

Toán Lớp 8: tìm x a, ( x+2)(x+3)-(x-2)(x-5)+6 b, 2x^2+x=0

Tháng Mười 28, 2022 Toán học 1 Comment 0 views

Toán Lớp 8: tìm x
a, ( x+2)(x+3)-(x-2)(x-5)+6
b, 2x^2+x=0

Comments ( 1 )

  1. baoquyen
    baoquyen
    28 Tháng Mười, 2022 at 8:39 chiều
    Reply
    a)(x+2)(x+3)-(x-2)(x-5)=6
    <=>(x^2+3x+2x+6)-(x^2-5x-2x+10)=6
    <=>x^2+3x+2x+6-x^2+5x+2x-10=6
    <=>12x=10
    <=>x=5/6
    Vậy: S={5/6}
    b)2x^2+x=0
    <=>x(2x+1)=0
    <=>\(\left[ \begin{array}{l}x=0\\2x+1=0\end{array} \right.\) 
    <=>\(\left[ \begin{array}{l}x=0\\x=-\dfrac{1}{2}\end{array} \right.\) 
    Vậy: S={0;-1/2}

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222-9+11+12:2*14+14 = ? ( )

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