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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x>0 biết: x(x^3y-x) -x^2(x^2y-2) =4

Toán Lớp 8: Tìm x>0 biết: x(x^3y-x) -x^2(x^2y-2) =4

Comments ( 2 )

  1. $x(x^3y-x)-x^2(x^2y-2) =4$
    $<=>x^4y-x^2-x^4y+2x^2=4$
    $<=>x^2=4$
    $<=>x=±2$
    $\text{Mà x > 0}$
    $=> x=2$

  2. x(x^3y-x)-x^2(x^2y-2)=4
    ⇔x. x^3y-x.x-x^2. x^2y+x^2.2=4
    ⇔x^4y-x^2-x^4y+2x^2=4
    ⇔(x^4y-x^4y)+(2x^2-x^2)=4
    ⇔x^2=4
    ⇔x^2=2^2
    ⇔x=±2
    Vì x>0 nê x=2 thỏa mãn bài toán.
     

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222-9+11+12:2*14+14 = ? ( )