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Toán Lớp 9: $\sqrt[3]{3}$`(`$5\sqrt[3]{18}$ – $\sqrt[3]{144}$`)` + $\sqrt[3]{5}$.$\sqrt[3]{50}$

Home/ Toán Lớp 9: $\sqrt[3]{3}$`(`$5\sqrt[3]{18}$ – $\sqrt[3]{144}$`)` + $\sqrt[3]{5}$.$\sqrt[3]{50}$

Toán Lớp 9: $\sqrt[3]{3}$`(`$5\sqrt[3]{18}$ – $\sqrt[3]{144}$`)` + $\sqrt[3]{5}$.$\sqrt[3]{50}$

Linh Tháng Chín 13, 2022 Toán học 2 Comments 0 views

Toán Lớp 9: $\sqrt[3]{3}$($5\sqrt[3]{18}$ – $\sqrt[3]{144}$) + $\sqrt[3]{5}$.$\sqrt[3]{50}$

Comments ( 2 )

chauhoangmy98
13 Tháng Chín, 2022 at 9:02 sáng

Reply

Giải đáp+Lời giải và giải thích chi tiết:

\root[3]{3}.(5\root[3]{18}-\root[3]{144})+\root[3]{5}.\root[3]{50}

=\root[3]{3}.5\root[3]{18}-\root[3]{3}.\root[3]{144}+\root[3]{5.50}

=\root[3]{3.18}.5-\root[3]{3.144}+\root[3]{2.125}

=\root[3]{27.2}.5-\root[3]{216.2}+5\root[3]{2}

=3.5\root[3]{2}-6\root[3]{2}+5\root[3]{2}

=15\root[3]{2}-6\root[3]{2}+5\root[3]{2}

=(15-6+5)\root[3]{2}

=14\root[3]{2}
quynhthanhnhu
13 Tháng Chín, 2022 at 9:02 sáng

Reply

$\sqrt[3]{a}$ ( 5$\sqrt[3]{18}$ – $\sqrt[3]{14}$ ) + $\sqrt[3]{5}$$\sqrt[3]{50}$

=15 $\sqrt[3]{2}$ + $\sqrt[3]{3}$ x ( – $\sqrt[3]{14}$ ) + $\sqrt[3]{5}$$\sqrt[3]{50}$

=15 $\sqrt[3]{2}$ – $\sqrt[3]{42}$ + $\sqrt[3]{50}$

=20$\sqrt[3]{2}$ – $\sqrt[3]{42}$

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