Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x, biết: a²x + 3ax + 9 = a² (với a $\neq$ 0; a $\neq$ -3)

Toán Lớp 8: Tìm x, biết:
a²x + 3ax + 9 = a² (với a $\neq$ 0; a $\neq$ -3)

Comments ( 1 )

  1. $a^2x + 3ax + 9 = a^2 (a\neq 0; a \neq -3) \\ ⇔ a^2x + 3ax = a^2 – 9 \\ ⇔ ax(a + 3) = (a – 3)(a + 3) \\ ⇔ x = \dfrac{(a – 3)(a + 3)}{x(a + 3)} \\⇔ x = \dfrac{a – 3}{a} \text{ (a $\neq $ 0; a $\neq $ -3)} \\ KL: x = \dfrac{a – 3}{a}$

Leave a reply

222-9+11+12:2*14+14 = ? ( )

About Tùy Linh