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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: tìm x a) x^2-2x+1 = 0 b) x^3 -4x=0

Toán Lớp 8: tìm x
a) x^2-2x+1 = 0
b) x^3 -4x=0

Comments ( 2 )

  1. a, x^2 – 2x +1 =0
    (x^2 – 2x.1 + 1^2 ) =0
    (x -1)^2 =0
    => x – 1=0
    => x =1
    b, x^3 – 4x =0
    x(x^2 – 4)=0
    x(x+2)(x-2)=0
    =>\(\left[ \begin{array}{l}x=0\\x+2=0\\x-2=0\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=0\\x=-2\\x=2\end{array} \right.\) 
    \text{Vậy} x ∈{0;-2;2}
     

  2. Giải đáp: + Lời giải và giải thích chi tiết:
    a)x^2-2x+1 = 0
    ⇔x^2-x-x+1 = 0
    ⇔x(x-1)-1.(x-1) = 0
    ⇔(x-1)(x-1) = 0
    ⇔x-1=0
    ⇔x=1
    Vậy: x=1
    b)x^3 -4x=0
    ⇔x.(x^2-2^2)=0
    ⇔x.(x-2).(x+2)=0
    $⇔\left[\begin{matrix} x=0\\ x-2=0\\x+2=0\end{matrix}\right.$
    $⇔\left[\begin{matrix} x=0\\ x=2\\x=-2\end{matrix}\right.$
    $⇔\left[\begin{matrix} x=0\\ x=\pm2\end{matrix}\right.$
    Vậy: x=0 hoặc x=±2

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222-9+11+12:2*14+14 = ? ( )