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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Thực hiện phép tính a) (3-2a) (a+1)+a(2a-1) b) x^2+9/x^2+3x + 6/x+3 với (x khác 0, x khác -3) c) 2+x/2-x + 4x^2/4-x^2 + x-2/2+x ( với

Toán Lớp 8: Thực hiện phép tính
a) (3-2a) (a+1)+a(2a-1)
b) x^2+9/x^2+3x + 6/x+3 với (x khác 0, x khác -3)
c) 2+x/2-x + 4x^2/4-x^2 + x-2/2+x ( với x khác 2, x khác -2)
d) (x^3+4x^2+6x+4) : x+2

Comments ( 2 )

  1. Bài làm:
    \(a)\)
    \((3-2a)\times(a+1)+a\times(2a-1)\)
    \(=3a+3-2a^2-2a+2a^2-a\)
    \(=0+3\)
    \(=3\)
    \(b)\)
    \(x^2+\dfrac{9}{x^2}+3x+\dfrac{6}{x}+3\)
    \(=\dfrac{x^4+9+3x^3+6x+3x^2}{x^2}\)
    \(=\dfrac{x^4+3x^3+3x^2+6x+9}{x^2}\)
    \(c)\)
    \(2+\dfrac{x}{2}-x + 4\times\dfrac{x^2}{4}-x^2 + x-\dfrac{2}{2}+x\)
    \(2+\dfrac{x}{2}+x^2-x^2-1+x\)
    \(=1+\dfrac{3}{2}x\)
    \(d)\)
    \((x^3+4x^2+6x+4) : x+2\)
    \(=\dfrac{x^3+4x^2+6x+4}{x}+2\)
    \(=\dfrac{x^3+4x^2+6x+4+2x}{x}\)
    \(=\dfrac{x^3+4x^2+8x+4}{x}\)
     

  2. Lời giải:
    a)
    (3-2a)(a+1)+a(2a-1)
    =3a+3-2a^(2)-2a+2a^(2)-a
    =(-2a^(2)+2a^2)+(3a-2a-a)+3
    =3
    b)
    (x^(2)+9)/(x^(2)+3x)+6/(x+3)       (x \ne 0; x \ne -3)
    =(x^(2)+9)/[x(x+3)]+(6x)/[x(x+3)]
    =(x^(2)+9+6x)/[x(x+3)]
    =(x^(2)+6x+9)/[x(x+3)]
    =(x+3)^(2)/[x(x+3)]
    =(x+3)/x
    c)
    (2+x)/(2-x)+(4x^2)/(4-x^2)+(x-2)/(2+x)    (x \ne ±2)
    =[(2+x)(2+x)]/[(2-x)(2+x)]+(4x^2)/[(2-x)(2+x)]+[(x-2)(2-x)]/[(2-x).(2+x)]    
    =[(2+x)^(2)+4x^(2)+(x-2)(2-x)]/[(2-x).(2+x)]  
    =(4+4x+x^(2)+4x^(2)+2x-x^(2)-4+2x)/[(2-x).(2+x)]  
    =[(4x^(2)-x^(2)+x^2)+(4x+2x+2x)+(4-4)]/[(2-x).(2+x)]  
    =(4x^(2)+8x)/[(2-x).(2+x)]  
    =[4x.(x+2)]/[(2-x)(x+2)]
    =(4x)/(2-x)
    d)
    (x^(3)+4x^(2)+6x+4):(x+2)
    =(x^(3)+2x^(2)+2x^(2)+4x+2x+4):(x+2)
    =[x^(2)(x+2)+2x(x+2)+2(x+2)]:(x+2)
    =(x^(2)+2x+2)(x+2):(x+2)
    =x^(2)+2x+2

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222-9+11+12:2*14+14 = ? ( )