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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: tìm x biết x(x-2) >hoặc bằng 0

Toán Lớp 7: tìm x biết x(x-2) >hoặc bằng 0

Comments ( 1 )

  1.     x(x-2)≥0
    ⇒\(\left[ \begin{array}{l}\left \{ {{x≥0} \atop {x-2≥0}} \right.\\\left \{ {{x≤0} \atop {x-2≤0}} \right.\end{array} \right.\)
    ⇒\(\left[ \begin{array}{l}\left \{ {{x≥0} \atop {x≥2}} \right.\\\left \{ {{x≤0} \atop {x≤2}} \right.\end{array} \right.\)
    ⇒\(\left[ \begin{array}{l}x≥2\\x≤0\end{array} \right.\) 
    Vậy x≥2 hoặc x≤0 
     

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222-9+11+12:2*14+14 = ? ( )

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