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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: 15 x (-1/5)^2 + 1/5 – 2 x (-1/2)^3 – 1/2

Home/ Toán Lớp 7: 15 x (-1/5)^2 + 1/5 – 2 x (-1/2)^3 – 1/2

Toán Lớp 7: 15 x (-1/5)^2 + 1/5 – 2 x (-1/2)^3 – 1/2

Tháng Tư 16, 2022 Toán học 2 Comments 0 views

Toán Lớp 7: 15 x (-1/5)^2 + 1/5 – 2 x (-1/2)^3 – 1/2

Comments ( 2 )

  1. daithanh
    daithanh
    16 Tháng Tư, 2022 at 8:49 sáng
    Reply
    15 xx (-1/5)^2 + 1/5 – 2 xx (-1/2)^3 – 1/2
    = 15 xx 1/25 + 1/5 – 2 xx (-1)/8 – 1/2
    = 3/5 + 1/5 – (-1)/4 – 1/2
    = 4/5 + 1/4 – 1/2
    = 21/20 – 1/2 = 11/20
     

  2. lanngocha
    lanngocha
    16 Tháng Tư, 2022 at 8:49 sáng
    Reply
    15 x (-1/5)^2 + 1/5 – 2 x (-1/2)^3 – 1/2
    = 15x . $\frac{1}{25}$ + $\frac{1}{5}$ – 2x (-1/2)^3 – $\frac{1}{2}$ 
    = $\frac{3}{5}$x + $\frac{1}{5}$ – 2x (-1/2)^3 – $\frac{1}{2}$ 
    = $\frac{3x}{5}$ + $\frac{1}{5}$ – 2x (-1/2)^3 – $\frac{1}{2}$
    = $\frac{3x}{5}$ + $\frac{1}{5}$ – 2x (-$\frac{1}{8}$) – $\frac{1}{2}$
    = $\frac{3x}{5}$ + $\frac{1}{5}$ + $\frac{1}{4}$x – $\frac{1}{2}$
    = $\frac{3x}{5}$ + $\frac{1}{5}$ + $\frac{1x}{4}$ – $\frac{1}{2}$
    = $\frac{3x}{5}$ + $\frac{1}{5}$ + $\frac{x}{4}$ – $\frac{1}{2}$
    = $\frac{3x}{5}$ – $\frac{3}{10}$ + $\frac{x}{4}$
    = $\frac{4.3x}{20}$ + $\frac{20.\frac{3}{10}}{20}$ + $\frac{5x}{20}$ 
    = $\frac{17x -6}{20}$ 

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222-9+11+12:2*14+14 = ? ( )

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