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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: câu a (3x+5) ×(2x-1)-6x ×(x+2)=x câu b x³ -5x ² -14x=0

Toán Lớp 8: câu a (3x+5) ×(2x-1)-6x ×(x+2)=x
câu b x³ -5x ² -14x=0

Comments ( 2 )

  1. a, (3x + 5)(2x – 1) – 6x(x + 2) = x
    <=> (6x^2 – 3x + 10x – 5) – 6x^2 – 12x = x
    <=> 6x^2 + 7x – 5 – 6x^2 – 12x = x
    <=> -5 – 5x = x
    <=> -5 – 5x – x = 0
    <=> -5 – 6x = 0
    <=> 6x = -5
    <=> x = -5/6
    Vậy x = -5/6
    b, x^3 – 5x^2 – 14x = 0
    <=> x(x^2 – 5x – 14) = 0
    <=> x(x^2 – 7x + 2x – 14) = 0
    <=> x[ x(x – 7) + 2(x – 7)] = 0
    <=> x(x + 2)(x – 7) = 0
    <=> \(\left[ \begin{array}{l}x=0\\x+2=0\\x-7=0\end{array} \right.\) 
    <=>\(\left[ \begin{array}{l}x=0\\x=-2\\x=7\end{array} \right.\) 
    Vậy x \in {0 ; -2 ; 7}

  2. Giải đáp + Lời giải và giải thích chi tiết:
    a,  (3x + 5 ) . (2x – 1 ) – 6x . ( x  + 2 )  = x
    <=> 6x^2 +7x – 5 – 6x ( x+2 ) = x 
     <=>- 5x – x = 5 
    <=>- 6x = 5 
    <=>6x = -5
    <=>x = -5 / 6
    Vậy x = -5 /6
     b , x^3 – 5x^2 – 14x = 0
    <=> ( x^2 – 5x – 14 ) = 0
    <=> x(x^2 + 2x – 7x – 14 ) = 0
    <=> x [ x ( x – 7 ) + 2(x – 7 ) ] = 0
    <=>$\left[\begin{matrix} x=0\\x+2=0\\ x-7 = 0\end{matrix}\right.$ <=>$\left[\begin{matrix} x = 0\\ x=-2\\x = 7\end{matrix}\right.$
    Vậy x = 0 ; x = -2 ; x = 7 

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222-9+11+12:2*14+14 = ? ( )

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