Toán Lớp 6: tìm n bt : a) -3/2n-1
b)-2/-n+2
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Toán Lớp 6: tìm n bt : a) -3/2n-1
b)-2/-n+2
Comments ( 1 )
a)
(-3)/(2n – 1)
=> -3 \vdots 2n – 1
=> 2n – 1 \in Ư(-3) = { -3; -1; 1; 3 }
=> n \in { -1; 0; 1; 2 }
b)
(-2)/(-n + 2)
=> -2 \vdots -n + 2
=> -n + 2 \in Ư(-2) = { -2; -1; 1; 2 }
=> -n \in { -4; -3; -1 }
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