Toán Lớp 8: {(x - 2)^2}/2 = x^2 - 4x + 4 tìm x

(x-2)^2/2=x^2-4x+4 <=>(x-2)^2=2(x^2-4x+4) <=>(x-2)^2=2(x-2)^2 <=>(x-2)^2-2(x-2)^2=0 <=>-(x-2)^2=0 <=>(x-2)^2=0 <=>x-2=0 <=>x=2 Vậy x=2

[(x-2)^2]/2 = x^2-4x+4 ⇔[(x-2)^2]/2 =(x-2)^2 ⇔(x-2)^2 = 2(x-2)^2 ⇔ (x-2)^2 - 2(x-2)^2=0 ⇔-(x-2)^2=0 ⇔(x-2)^2 =0 ⇔x-2 =0 ⇔x=2

Toán Lớp 8: `{(x - 2)^2}/2 = x^2

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