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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x biết: a)x2+5x=0 b)(2x+3)(2x-3)-4x(x+2)=3 c)3x(x-1)=1-x

Toán Lớp 8: Tìm x biết:
a)x2+5x=0
b)(2x+3)(2x-3)-4x(x+2)=3
c)3x(x-1)=1-x

Comments ( 2 )

  1. $a,$ $x^{2}+5x=0$
    $⇒$ $x(x+5)=0$
    $⇒$ \(\left[ \begin{array}{l}x=0\\x+5=0⇒x=-5\end{array} \right.\) 
    $b,$ $(2x+3)(2x-3)-4x(x+2)=3$ 
    $⇒$ $4x^2-9-4x^2-8x=3$ 
    $⇒$ $-9-8x=3$ 
    $⇒$ $-8x=12$ 
    $⇒$ $x=\dfrac{-3}{2}$ 
    $c,$ $3x(x-1)=1-x$ 
    $⇒$$3x^2-2x-1=0$
    $⇒$$(x-1)(3x+1)=0$
    $⇒$\(\left[ \begin{array}{l}x=1\\x=\dfrac{-1}{3} \end{array} \right.\) 
     

  2. a) x^2+5x=0
    <=> x(x+5)=0
    TH1:
    x=0
    TH2:
    x+5=0
    <=> x=-5
    Vậy x∈{0;-5}
    b) (2x+3)(2x-3)-4x(x+2)=3
    <=> 4x^2-9-4x^2-8x=3
    <=> -9-8x=3
    <=> -8x=3+9
    <=> -8x=12
    <=> x=-12/8
    <=> x=-3/2
    Vậy x=-3/2
    c) 3x(x-1)=1-x
    <=> 3x^2-3x=1-x
    <=> 3x^2-3x-1+x=0
    <=> 3x^2-2x-1=0
    <=> (3x+1)(x-1)=0
    TH1:
    3x+1=0
    <=> 3x=-1
    <=> x=-1/3
    TH2:
    x-1=0
    <=> x=1
    Vậy x∈{-1/3;1}

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222-9+11+12:2*14+14 = ? ( )