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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tìm x (2x+3) ² = $\frac{36}{25}$

Toán Lớp 7: Tìm x
(2x+3) ² = $\frac{36}{25}$

Comments ( 2 )

  1. Answer
    (2x + 3)^{2} = 36/25
    => (2x + 3)^{2} = (+-6/5)^{2}
    => 2x + 3 = +-6/5
    => $\left[\begin{matrix} 2x + 3 = \dfrac{6}{5}\\ 2x + 3 = \dfrac{-6}{5}\end{matrix}\right.$
    => $\left[\begin{matrix} 2x = \dfrac{6}{5} – 3\\ 2x = \dfrac{-6}{5} – 3\end{matrix}\right.$
    => $\left[\begin{matrix} 2x = \dfrac{-9}{5}\\ 2x = \dfrac{-21}{5}\end{matrix}\right.$
    => $\left[\begin{matrix} x = \dfrac{-9}{5} : 2\\ x = \dfrac{-21}{5} : 2\end{matrix}\right.$
    => $\left[\begin{matrix} x = \dfrac{-9}{10}\\ x = \dfrac{-21}{10}\end{matrix}\right.$
    $\text{Vậy}$ x \in {-9/10 ; -21/10}

  2. Giải đáp + Lời giải và giải thích chi tiết :
    ( 2x + 3 )^2 = 36/25
    ⇔ 2x + 3 = ± 6/5
    ⇔ \(\left[ \begin{array}{l}2x+3=\frac{6}{5}\\2x+3=-\frac{6}{5}\end{array} \right.\)
    ⇔ \(\left[ \begin{array}{l}2x=\frac{6}{5}-3\\2x=-\frac{6}{5}-3\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}2x=\frac{6}{5}-\frac{15}{5}\\2x=-\frac{6}{5}-\frac{15}{5}\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}2x=\frac{-9}{5}\\2x=-\frac{21}{5}\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}x=\frac{-9}{5}:2\\x=-\frac{21}{5}:2\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}x=-\frac{9}{10}\\x=-\frac{21}{10}\end{array} \right.\) 
    $# Mon $
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222-9+11+12:2*14+14 = ? ( )

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