Toán Lớp 8: Tính
$\frac{x}{x+1}$ + $\frac{3x+1}{x^2-1}$
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Toán Lớp 8: Tính
$\frac{x}{x+1}$ + $\frac{3x+1}{x^2-1}$
Comments ( 2 )
= {x(x-1)}/{(x+1)(x-1)} + {3x+1}/{(x+1)(x-1)}
= {x^2 – x +3x +1}/{(x+1)(x-1)}
= {x^2 +2x +1}/{(x+1)(x-1)}
= {(x+1)^2 }/{(x+1)(x-1)}
={x+1}/{x-1}