Toán Lớp 8: $\frac{1}{3y-1}$-$\frac{1}{3y+1}$- $\frac{2y-3}{1-9y{2}}$
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Toán Lớp 8: $\frac{1}{3y-1}$-$\frac{1}{3y+1}$- $\frac{2y-3}{1-9y{2}}$
Comments ( 2 )
= -1/(1-3y)-1/(1+3y)-(2y-3)/((1-3y)(1+3y))
= ((-1).(1+3y))/((1-3y)(1+3y)) – (1.(1-3y))/((1-3y)(3y+1)) – (2y-3)/((1-3y)(1+3y))
= (-1-3y-1+3y-2y+3)/((1-3y)(1+3y))
= (-2y+1)/((1-3y)(1+3y))