Toán Lớp 8: $\frac{x^{2}-1}{x+10}$. $\frac{x}{x+2}$+ $\frac{x^{2}-1}{x+10}$. $\frac{1-x}{x+2}$ rút gọn
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Toán Lớp 8: $\frac{x^{2}-1}{x+10}$. $\frac{x}{x+2}$+ $\frac{x^{2}-1}{x+10}$. $\frac{1-x}{x+2}$ rút gọn
Comments ( 2 )
\frac{{{x^2} – 1}}{{x + 10}}.\frac{x}{{x + 2}} + \frac{{{x^2} – 1}}{{x + 10}}.\frac{{1 – x}}{{x + 2}}\\
= \frac{{{x^2} – 1}}{{x + 10}}.\left( {\frac{{x + 1 – x}}{{x + 2}}} \right)\\
= \frac{{{x^2} – 1}}{{x + 10}}.\frac{1}{{x + 2}}\\
= \frac{{{x^2} – 1}}{{\left( {x + 10} \right)\left( {x + 2} \right)}}
\end{array}\]