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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: a) x^2-4x=0 b)x(x+3)-2x-6=0 c)x^3+27+(x+3)(x-9)=0

Toán Lớp 8: a) x^2-4x=0
b)x(x+3)-2x-6=0
c)x^3+27+(x+3)(x-9)=0

Comments ( 2 )

  1. Giải đáp + Lời giải và giải thích chi tiết:
     a)
    x²-4x=0
    ⇔ x(x-4)=0
    ⇔ $\left[\begin{matrix} x=0\\ x-4=0\end{matrix}\right.$
    ⇔ $\left[\begin{matrix} x=0\\ x=4\end{matrix}\right.$
    Vậy x=0 hoặc x=4
    b)
    x(x+3)-2x-6=0
    ⇔x(x+3)-2(x+3)=0
    ⇔ (x+3)(x-2)=0
    ⇔ $\left[\begin{matrix} x+3=0\\ x-2=0\end{matrix}\right.$
    ⇔ $\left[\begin{matrix} x=-3\\ x=2\end{matrix}\right.$
    Vậy x=-3 hoặc x=2
    c)
    x³+27+(x+3)(x-9)=0
    ⇔(x+3)(x²-3x+9)+(x+3)(x-9)=0
    ⇔ (x+3)(x²-3x+9+x-9)=0
    ⇔ (x+3)(x²-2x)=0
    ⇔ x(x+3)(x-2)=0
    ⇔ $\left[\begin{matrix} x=0\\ x+3=0\\x-2=0\end{matrix}\right.$
    ⇔ $\left[\begin{matrix} x=0\\ x=-3\\x=2\end{matrix}\right.$
    Vậy x∈{0;-3;2}

  2. $a) x^2 – 4x = 0$
           $x(x – 4)  = 0$
    \(\left[ \begin{array}{l}x=0\\x-4=0\end{array} \right.\)
    \(\left[ \begin{array}{l}x=0\\x=4\end{array} \right.\)
    $Vậy: x = 0  hoặc  x = 4$.
    $b) x(x + 3) – 2x – 6 = 0$
        $x(x + 3) – 2(x + 3)= 0$
            $(x + 3)(x – 2)    = 0$
    \(\left[ \begin{array}{l}x+3=0\\x-2=0\end{array} \right.\)
    \(\left[ \begin{array}{l}x=-3\\x=2\end{array} \right.\)
    $Vậy: x =-3  hoặc  x = 2$
    $c)    x^3 + 27 + (x + 3)(x – 9) = 0$
          $x^3 + 3^3 + (x + 3)(x – 9) = 0$
    $(x + 3)(x^2 + 3x + 9) + (x + 3)(x – 9) = 0$
       $(x + 3)(x^2 + 3x + 9 + x – 9) = 0$
                        $ (x + 3)(x^2 + 4x) = 0$
                            $x(x + 3)(x + 4)  = 0$
    $=>* x =0$
          $* x + 3 =0 → x = -3$
           $* x + 4 =0 → x = -4$
    $Vậy: x = 0; x = -3  hoặc  x = -4$
    Học tốt.
      
        

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222-9+11+12:2*14+14 = ? ( )

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