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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: `(“(x – 3)/x` `-` `x/(x – 3)` `+` `9/(x² – 3x)“)` `.` `x/(2x – 2)`

Tháng Tám 9, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: ((x – 3)/x – x/(x – 3) + 9/(x² – 3x)) . x/(2x – 2)

Comments ( 2 )

  1. thanoanghha
    thanoanghha
    9 Tháng Tám, 2022 at 8:24 chiều
    Reply
    ĐKXĐ: x \ne 0 ; x \ne 3
    Ta có: x^2 – 3x = x ( x – 3 )
    (  $\dfrac{x – 3}{x}$ – $\dfrac{x}{x – 3}$ + $\dfrac{9}{x^2-3x}$  )  . $\dfrac{x}{2x -2}$
    = ( $\dfrac{(x – 3)^2}{x ( x – 3 )}$ – $\dfrac{x^2}{x ( x – 3 )}$ + $\dfrac{9}{x^2-3x}$ )  . $\dfrac{x}{2x -2}$
    =  $\dfrac{( x – 3 )^2 – x^2 + 9}{x(x – 3)}$ . $\dfrac{x}{2x -2}$
    = $\dfrac{ x^2 – 6x +9 – x^2 + 9}{x(x – 3)}$ . $\dfrac{x}{2x -2}$
    =  $\dfrac{ x^2 – 6x +9 – x^2 + 9}{x(x – 3)}$ . $\dfrac{x}{2(x -1)}$
    = $\frac{- 2.3(x -3)}{ x – 3}$ .  $\dfrac{1}{2(x -1)}$
    = $\frac{- 3 }{x – 1}$ 

  2. daolanhoa
    daolanhoa
    9 Tháng Tám, 2022 at 8:23 chiều
    Reply
    Giải đáp + Lời giải và giải thích chi tiết:
    ((x-3)/x-x/(x-3)+9/(x^2-3x)). x/(2x-2)(x\ne0;x\ne3;x\ne1)
    =[((x-3)(x-3))/(x(x-3))-(x.x)/(x(x-3))+9/(x^2-3x)]. x/(2x-2)
    =(x^2-6x+9-x^2+9)/(x^2-3x). x/(2x-2)
    =(18-6x)/(x(x-3)) .x/(2x-2)
    =(-6(x-3))/(x-3). x/(2(x-1))
    =(-6). x/(2(x-1))
    =(-6x)/(2(x-1))
    =(-3x)/(x-1)

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222-9+11+12:2*14+14 = ? ( )

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