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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: ($\frac{1}{2}$ + $\frac{-2}{3}$)$^{2}$ – $\frac{40}{36}$

Home/ Toán Lớp 7: ($\frac{1}{2}$ + $\frac{-2}{3}$)$^{2}$ – $\frac{40}{36}$

Toán Lớp 7: ($\frac{1}{2}$ + $\frac{-2}{3}$)$^{2}$ – $\frac{40}{36}$

Tháng Bảy 29, 2022 Toán học 2 Comments 0 views

Toán Lớp 7: ($\frac{1}{2}$ + $\frac{-2}{3}$)$^{2}$ – $\frac{40}{36}$

Comments ( 2 )

  1. quynhthanhnhu
    quynhthanhnhu
    29 Tháng Bảy, 2022 at 2:09 chiều
    Reply
    $( \dfrac{1}{2} + \dfrac{-2}{3} )^2$ $-$ $\dfrac{40}{36}$
    $=$ $( \dfrac{3}{6} + \dfrac{-4}{6} )^2$ $-$ $\dfrac{40}{36}$
    $=$ $( \dfrac{-1}{6} )^2$ $-$ $\dfrac{40}{36}$
    $=$ $\dfrac{1}{36}$ $-$ $\dfrac{40}{36}$
    $=$ $\dfrac{1 – 40}{36}$
    $=$ $\dfrac{-13}{12}$

  2. diepbich93
    diepbich93
    29 Tháng Bảy, 2022 at 2:09 chiều
    Reply
    (1/2+(-2)/3)^2 -40/36
    =(-1/6)^2 -10/9
    =1/36-10/9
    =-13/12
     

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222-9+11+12:2*14+14 = ? ( )

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