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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 1, x^2-2xy+2y-4y 2, 4x^2-y^2+8y-16

Toán Lớp 8: 1, x^2-2xy+2y-4y
2, 4x^2-y^2+8y-16

Comments ( 2 )

  1. Giải đáp:
    $\begin{array}{l}
    1){x^2} – 2xy + 2x – 4y\\
     = x\left( {x – 2y} \right) + 2\left( {x – 2y} \right)\\
     = \left( {x – 2y} \right)\left( {x + 2} \right)\\
    2)\\
    4{x^2} – {y^2} + 8y – 16\\
     = 4{x^2} – \left( {{y^2} – 8y + 16} \right)\\
     = {\left( {2x} \right)^2} – {\left( {y – 4} \right)^2}\\
     = \left( {2x – y + 4} \right)\left( {2x + y – 4} \right)
    \end{array}$

  2. $\\$
    1,
    x^2-2xy+2x-4y
    =(x^2-2xy)+(2x-4y)
    =x(x-2y)+2(x-2y)
    =(x-2y)(x+2)
    2,
    4x^2-y^2+8y-16
    =4x^2-(y^2-8y + 16)
    =(2x)^2-(y^2-2.y.4+4^2)
    =(2x)^2-(y-4)^2
    =(2x-y+4)(2x+y-4)
     

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222-9+11+12:2*14+14 = ? ( )