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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: a) (x+1).(x+4)>0 b)(x-4).(x+3)=0 Giúp em với ạ em cảm ơn

Toán Lớp 6: a) (x+1).(x+4)>0 b)(x-4).(x+3)=0 Giúp em với ạ em cảm ơn

Comments ( 2 )

  1. Answer
    $\text{a, Ta có:}$ (x + 1) . (x + 4) > 0
    => x + 1 ; x + 4 $\text{cùng dấu}$
    => $\left[\begin{matrix} \begin{cases} x + 1 > 0\\x + 4 > 0 \end{cases}\\ \begin{cases} x + 1 < 0\\x + 4 < 0 \end{cases}\end{matrix}\right.$
    => $\left[\begin{matrix} \begin{cases} x > 0 – 1\\x > 0 – 4 \end{cases}\\ \begin{cases} x < 0 – 1\\x < 0 – 4 \end{cases}\end{matrix}\right.$
    => $\left[\begin{matrix} \begin{cases} x > – 1\\x > – 4 \end{cases}\\ \begin{cases} x < – 1\\x < – 4 \end{cases}\end{matrix}\right.$
    =>  $\left[\begin{matrix} \begin{cases} x > – 1\\x < – 4 \end{cases}\text{(chọn)} \\ \begin{cases} x < – 1\\x > – 4 \end{cases}\text{(loại)} \end{matrix}\right.$
    => -4 < x < -1
    $\text{Vậy}$ -4 < x < -1
    __________________________
    b, (x – 4) . (x + 3) = 0
    => $\left[\begin{matrix} x – 4 = 0\\ x + 3 = 0\end{matrix}\right.$
    => $\left[\begin{matrix} x = 0 + 4\\ x = 0 – 3\end{matrix}\right.$
    => $\left[\begin{matrix} x = 4\\ x = – 3\end{matrix}\right.$
    $\text{Vậy}$ x \in {4 ; -3}

  2. Giải đáp:
    $a)  \left[\begin{array}{l} x >-1\\ x<-4\end{array} \right.\\ b) \left[\begin{array}{l} x=4 \\ x=-3\end{array} \right..$
    Lời giải và giải thích chi tiết:
    $a) (x+1)(x+4)>0\\ \Leftrightarrow \left[\begin{array}{l} \left\{\begin{array}{l} x+1 >0 \\ x+4>0\end{array} \right. \\ \left\{\begin{array}{l} x+1<0 \\ x+4<0\end{array} \right.\end{array} \right.\\ \Leftrightarrow \left[\begin{array}{l} \left\{\begin{array}{l} x >-1 \\ x>-4\end{array} \right. \\ \left\{\begin{array}{l} x<-1 \\ x<-4\end{array} \right.\end{array} \right.\\ \Leftrightarrow \left[\begin{array}{l} x >-1\\ x<-4\end{array} \right.\\ b)(x-4)(x+3)=0\\ \Leftrightarrow \left[\begin{array}{l} x-4=0 \\ x+3=0\end{array} \right.\\ \Leftrightarrow \left[\begin{array}{l} x=4 \\ x=-3\end{array} \right..$

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222-9+11+12:2*14+14 = ? ( )

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