Toán Lớp 8: a) (3x+1)^2 – x^2+8x-16=0
b) x-1/34 + x-5/10 + x/7 + x-100034/1111 =0
Leave a reply
Register Now
Login
Lost Password
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Toán Lớp 8: a) (3x+1)^2 – x^2+8x-16=0
b) x-1/34 + x-5/10 + x/7 + x-100034/1111 =0
Comments ( 1 )
$ (3x+1)^2 – x^2+8x-16=0 $
$ ⇒ 9x^2 + 6x + 1 – x^2 + 8x – 16 = 0 $
$ ⇒ 8x^2 +14x -15 = 0 $
$ ⇒ $ \(\left[ \begin{array}{l}x=\dfrac{3}{4}\\x=-\dfrac{5}{2}\end{array} \right.\)