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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Giải phương trình 3-2x=7 3(x-2)-5(x+1)=3 x(x-2)-x(x+1)=15 (3x-1)(2x+5)-(2x-3)(3x+4)=7 (x-1) ²+(x-2) ²=2(x+4) ²-(22x+27) 3x(12x-4)-9x(4x

Toán Lớp 8: Giải phương trình
3-2x=7
3(x-2)-5(x+1)=3
x(x-2)-x(x+1)=15
(3x-1)(2x+5)-(2x-3)(3x+4)=7
(x-1) ²+(x-2) ²=2(x+4) ²-(22x+27)
3x(12x-4)-9x(4x-3)=30
Cần gấp ạ Hứa vote5*

Comments ( 1 )

  1. $a) 3 – 2x = 7$
    $⇔ -2x = 4$
    $⇔ x = -2$

    $b) 3(x – 2)-5(x + 1) = 3$

    $⇔ 3x – 6 – 5x -1 = 3$
    $⇔ -2x -7 = 3$
    $⇔ -2x = 10$
    $⇔ x = -5$
    $c) x(x – 2)-x(x + 1) = 15$
    $⇔ x^2 – 2x – x^2 -1 = 15$
    $⇔ -2x -1 = 15$
    $⇔ -2x = 16$
    $⇔ x = -8$
    $d) (3x – 1)(2x + 5)-(2x – 3)(3x + 4) = 7$
    $⇔ (6x^2 – 2x + 15x -5) – (6x^2 – 9x + 8x – 12) = 7$
    $⇔ 6x^2 + 13x – 5 – 6x^2 + x + 12 = 7$
    $⇔ 14x + 7 = 7$
    $⇔ 14x = 0$
    $⇔ x = 0$
    $e) (x – 1)^2 + (x – 2)^2 = 2(x+4)^2 – (22x + 27)$
    $⇔ x^2 -2x +1 + x^2 -4x +4= 2x^2 + 16x +32 – 22x – 27$
    $⇔2x^2 -6x +5 = 2x^2 – 6x +5$
    $⇔(2x^2 -6x +5) – (2x^2 -6x +5) = 0$
    $⇔ 0x = 0$
    $⇔ x ∈ R$

    $ g) 3x(12x-4)-9x(4x-3)=30$
    $⇔36x^2 -12x – 36x^2+27x=30$
    $⇔15x = 30$
    $⇔ x =2$

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222-9+11+12:2*14+14 = ? ( )