Toán Lớp 10: Giải phương trình
$2\sqrt{3-2x}=|x-1|$
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Toán Lớp 10: Giải phương trình
$2\sqrt{3-2x}=|x-1|$
Comments ( 1 )
\quad 2\sqrt{3-2x} = |x-1|\qquad \left(x \leqslant \dfrac32\right)\\
\Rightarrow 4(3-2x)=x^2 -2x +1\\
\Leftrightarrow x^2 +6x -11=0\\
\Leftrightarrow \left[\begin{array}{l}x =-3 – 2\sqrt5\\x = – 3 + 2\sqrt5\end{array}\right.\quad \text{(nhận)}\\
\text{Vậy}\ S = \left\{-3 – 2\sqrt5;-3+2\sqrt5\right\}
\end{array}\)