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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 12: Đạo hàm $3x^2-6x+ln(x+1)^{3}+1$

Toán Lớp 12: Đạo hàm $3x^2-6x+ln(x+1)^{3}+1$

Comments ( 1 )

  1. $\quad y = 3x^2 – 6x + \ln(x+1)^3 + 1\qquad (x> -1)$
    $\to y = 3x^2 – 6x + 3\ln(x+1) + 1$
    $\to y’ = (3x^2)’ – (6x)’ + 3\cdot [\ln(x+1)]’$
    $\to y’ = 6x – 6 + \dfrac{3}{x+1}$

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222-9+11+12:2*14+14 = ? ( )