Toán Lớp 8: Giải phương trình
(x-3).(2x+5)=0
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Toán Lớp 8: Giải phương trình
(x-3).(2x+5)=0
Comments ( 2 )
(x-3)(2x+5)=0
\(⇔\left[ \begin{array}{l}x-3=0\\2x+5=0\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=3\\x=-\frac{5}{2}\end{array} \right.\)
Vậy x=3 hoặc x=-5/2
Giải đáp:
$(x-3).(2x+5)=0$
$⇔$ \(\left[ \begin{array}{l}x-3=0\\2x+5=0\end{array} \right.\) $⇔$ \(\left[ \begin{array}{l}x=0+3\\2x=-5\end{array} \right.\) $⇔$ \(\left[ \begin{array}{l}x=3\\x=\dfrac{-5}{2}\end{array} \right.\)
$\text{Vậy x= 3 hoặc x=}$ $\dfrac{-5}{2}$