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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: a, -27+34+(-173)+(-50)+166 b,100-[70-(5-8) mũ 2 .3] c, 2018 mũ 0 -{10 mũ 2 :[20.15-2 mũ 3 .5 mũ 2 ]-25}

Tháng Ba 25, 2022 Toán học 2 Comments 0 views

Toán Lớp 6: a, -27+34+(-173)+(-50)+166
b,100-[70-(5-8) mũ 2 .3]
c, 2018 mũ 0 -{10 mũ 2 :[20.15-2 mũ 3 .5 mũ 2 ]-25}

Comments ( 2 )

  1. hienthucthu97
    hienthucthu97
    25 Tháng Ba, 2022 at 7:19 sáng
    Reply
    a,
    -27+34+(-173)+(-50)+166
    =[(-27)+(-173)]+[166+34]+(-50)
    =(-200)+200+(-50)
    =0+(-50)
    =-50
    $\\$
    b,
    100-[70-(5-8)^2 .3]
    =100-[70-(-3)^2. 3]
    =100-[70-9.3]
    =100-[70-27]
    =100-43
    =57
    $\\$
    c,
    2018^0 -{10^2 :[20.15-2^3 .5^2]-25}
    =2018^0-{10^2:[20.15-8.25]-25}
    =1-{10^2:[300-200]-25}
    =1-{100:100-25}
    =1-{1-25}
    =1-(-24)
    =1+24
    =25

  2. minhtamnguyet88
    minhtamnguyet88
    25 Tháng Ba, 2022 at 7:19 sáng
    Reply
    $a,-27+34+(-173)+(-50)+166^{}$
    $=[(-27)+(-173)]+[34+166]+(-50) ^{}$
    $=[-200+200]+-50^{}$
    $=0+(-50)^{}$
    $=-50^{}$
    $b,100-[70-(5-8)^{}$ $^{2.3}]$
    $= 100 – (-658)^{}$
    $= 758^{}$
    $c,^{}$ $2018^{0}$ $- ^{}$ { $10^{2}$ $:^{}$ $[20 . 15 – ^{}$ $2^{3}$$.^{}$ $5^{2}$$]^{}$ $-25^{}$}
    $= 1 – ^{}$ {$100 : [300-200] – 25^{}$}
    $= 1 – (-24)^{}$
    $= 25^{}$
     

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222-9+11+12:2*14+14 = ? ( )

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