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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Cho A=1+2^1+2^2+2^3+…+2^99+2^100+2^201.Chứng minh:A chia hết cho 7

Home/ Toán Lớp 6: Cho A=1+2^1+2^2+2^3+…+2^99+2^100+2^201.Chứng minh:A chia hết cho 7

Toán Lớp 6: Cho A=1+2^1+2^2+2^3+…+2^99+2^100+2^201.Chứng minh:A chia hết cho 7

Tháng Tư 12, 2023 Toán học 2 Comments 0 views

Toán Lớp 6: Cho A=1+2^1+2^2+2^3+…+2^99+2^100+2^201.Chứng minh:A chia hết cho 7

Comments ( 2 )

  1. haiyemy
    haiyemy
    12 Tháng Tư, 2023 at 8:17 chiều
    Reply
    A = 1 + 2^1 + 2^2 + … + 2^100 + 2^101
    A = (1 + 2 + 2^2) + (2^3 + 2^4 + 2^5) + … + (2^99 + 2^100 + 2^101)
    A = (1 + 2 +2^2) + 2^2 . (1 + 2 +2^2) + … + 2^99 . (1 + 2 +2^2)
    A = (1 + 2 +2^2) . (1 + 2^2 + 2^6 + … + 2^99)
    A = 7 . (1 + 2^2 + 2^6 + … + 2^99) \vdots 7
    A \vdots 7 (đpcm)
    Vậy: A = 1 + 2^1 + 2^2 + … + 2^100 + 2^101 \vdots 7

  2. ngoclanquynh
    ngoclanquynh
    12 Tháng Tư, 2023 at 8:17 chiều
    Reply
    A=1+2^1+2^2+2^3+…………………+2^99+2^100+2^101
    A=(1+2^1+2^2)+(2^3+2^4+2^5)+…………………..+(2^99+2^100+2^101)
    A=1.(1+2^1+2^2)+2^3.(1+2^1+2^2)+………………….+2^99.(1+2^1+2^2)
    A=1.7+2^3. 7+………………..+2^99. 7
    A=7.(1+2^3+…………..+2^99)
    Vì 7vdots7
    =>Avdots7
    Vậy Avdots7
     

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222-9+11+12:2*14+14 = ? ( )

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