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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: a)-23+150+(-9)+1913 b)1125:3^2-4^3.125:5^2 c)(15+21)-(25-15-35-21) d)5(x-9)=350 e)(2x+2^5).8^24=8^26 g)105^x.105^3=105^7

Toán Lớp 6: a)-23+150+(-9)+1913
b)1125:3^2-4^3.125:5^2
c)(15+21)-(25-15-35-21)
d)5(x-9)=350
e)(2x+2^5).8^24=8^26
g)105^x.105^3=105^7

Comments ( 2 )

  1. Giải đáp:
     $a) (-23)+150+(-9)+1913$
    $= [(-23)+1913]+[150+(-9)]$
    $= 1890+141$
    $= 2031$
    $b) 1125:3²-4³.125:5²$
    $= 1125:9-64.125:25$
    $= 125-8000:25$
    $= 125-320$
    $= -195$
    $d) 5.(x-9)=350$
    $⇔ x-9= 350:5$
    $⇔ x-9= 70$
    $⇔ x= 70+9$
    $⇔x=79$
    $Vậy$ $x=79$
    $c) (15+21)-(25-15-35-21)$
    $= 15+21-25+15+35+21$
    $= (15+15+35-25)+(21+21)$
    $= 40+42$
    $=82$
    $e) (2x+2^5).8^{24}=8^{26}$
    $⇔ (2x+32)= 8^{26}:8^{24}$
    $⇔ 2x+32= 8^{26-24}$
    $⇔ 2x+32= 64$
    $⇔ 2x= 32$
    $⇔ x= 32:2$
    $⇔x= 16$
    $Vậy$ $x=16$
    $g) 105^{x}.105^3= 105^7$
    $⇔ 105^{x}= 105^7:105^3$
    $⇔ 105^{x}= 105^{7-3}$
    $⇔ 105^{x}=105^{4}$
    $⇔ x=4$
    $Vậy$ $x=4$
     

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222-9+11+12:2*14+14 = ? ( )