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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: $\frac{1}{x+2}$ +$\frac{1}{x-2}$ helppppppppppppppp

Toán Lớp 8: $\frac{1}{x+2}$ +$\frac{1}{x-2}$
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Comments ( 2 )

  1. Giải đáp:
     
    Lời giải và giải thích chi tiết:
    ĐKXĐ : x $\neq$ ± 2
    $\frac{1}{x + 2}$ + $\frac{1}{x – 2}$ 
    = $\frac{x – 2}{(x + 2)(x – 2)}$ + $\frac{x + 2}{(x – 2)(x + 2)}$ 
    = $\frac{x – 2 + x + 2}{(x + 2)(x – 2)}$
    = $\frac{2x}{(x + 2)(x – 2)}$

  2. $\frac{1}{x+2}$+$\frac{1}{x-2}$ ĐKXĐ : x
    =$\frac{1((x-2)+1(x+2)}{(x-2)(x+2)}$ 
    =$\frac{x-2+x+2}{(x-2)(x+2)}$ 
    =$\frac{2x}{(x-2)(x+2)}$ 
     
     

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222-9+11+12:2*14+14 = ? ( )