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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x biết: `(x^2-x)(x^2-x-2)=24`

Toán Lớp 8: Tìm x biết: (x^2-x)(x^2-x-2)=24

Comments ( 1 )

  1. Giải đáp:
    x in{-2;3}
    Lời giải và giải thích chi tiết:
     (x^2-x)(x^2-x-2)= 24
    <=> x^4- x^3- 2x^2- x^3+x^2+ 2x= 24
    <=> x^4- 2x^3- x^2+ 2x= 24
    <=> x^4- 2x^3- x^2+ 2x- 24=0
    <=> x^4+2x^3- 4x^3- 8x^2+ 7x^2+ 14x- 12x- 24= 0
    <=> x^3(x+2)- 4x^2(x+2)+ 7x(x+2)- 12(x+2)=0
    <=> (x+2)(x^3- 4x^2+ 7x- 12) =0
    <=> (x+2)(x^3- 3x^2- x^2+ 3x+ 4x- 12) =0
    <=> (x+2)[x^2(x-3)-x(x-3)+4(x-3)]= 0
    <=> (x+2)(x-3)(x^2-x+4)=0
    <=>\(\left[ \begin{array}{l}x+2=0\\x-3= 0\end{array} \right.\) hoặc x^2-x+4=0
    <=> \(\left[ \begin{array}{l}x=-2\\x=3\end{array} \right.\) 
    Vậy x in{-2;3}

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222-9+11+12:2*14+14 = ? ( )