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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: e) 2x – 49 = 5.32 i) 5 . ( x – 2) = 0 f) 2(x- 51) = 2.23 + 20 j) (5 – x) . (x + 7) = 0 g) 4(x – 3) = 72 – 110 k) (3x + 9).(5x – 15) = 0

Toán Lớp 6: e) 2x – 49 = 5.32 i) 5 . ( x – 2) = 0
f) 2(x- 51) = 2.23 + 20 j) (5 – x) . (x + 7) = 0
g) 4(x – 3) = 72 – 110 k) (3x + 9).(5x – 15) = 0
h) 484 + x = – 632 + (-548)

Comments ( 1 )

  1. e) 2x – 49 = 5 . 32
    <=> 2x – 49 = 160
    <=> 2x = 160 + 49
    <=> 2x = 209
    <=> x = 209/2
    Vậy x = 209/2
    $\\$
    f) 2(x – 51) = 2 . 23 + 20
    <=> 2x – 102 = 46 + 20
    <=> 2x – 102 = 66
    <=> 2x = 66 + 102
    <=> 2x = 168
    <=> x = 84
    Vậy x = 84
    $\\$
    g) 4(x – 3) = 72 – 110
    <=> 4x – 12 = – 38
    <=> 4x = 12 – 38
    <=> 4x = – 26
    <=> x = – 26/4
    <=> x = – 13/2
    Vậy x = – 13/2
    $\\$
    h) 484 + x = – 632 + (- 548)
    <=> 484 + x = – 632 – 548
    <=> 484 + x = 1180
    <=> x = 1180 – 484
    <=> x = 696
    Vậy x = 696
    $\\$
    i) 5(x – 2) = 0
    => $\left[\begin{matrix} 5 = 0 (loại) \\ x – 2 = 0\end{matrix}\right.$
    <=> x = 2
    Vậy x = 2
    $\\$
    j) (5 – x)(x + 7) = 0
    => $\left[\begin{matrix} 5 – x = 0\\ x + 7 = 0\end{matrix}\right.$
    <=> $\left[\begin{matrix} x = 5\\ x = – 7\end{matrix}\right.$
    Vậy x = 5 hoặc x = – 7
    $\\$
    k) (3x + 9)(5x – 15) = 0
    => TH1: 3x + 9 = 0
    <=> 3x = – 9
    <=> x = – 3
    => TH2: 5x – 15 = 0
    <=> 5x = 15
    <=> x = 3
    Vậy x = – 3 hoặc x = 3
    $#Ling$
     

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222-9+11+12:2*14+14 = ? ( )