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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Thực hiện phép tính 1) $\frac{x+3}{2x+1}$ – $\frac{x-7}{2x+1}$ 2) $\frac{x-3}{x^2-2x}$ + $\frac{2x-5}{x^2+4x+4}$

Toán Lớp 8: Thực hiện phép tính
1) $\frac{x+3}{2x+1}$ – $\frac{x-7}{2x+1}$
2) $\frac{x-3}{x^2-2x}$ + $\frac{2x-5}{x^2+4x+4}$

Comments ( 2 )

  1. Giải đáp + giải thích các bước giải:
    1, (x +3)/(2x + 1) – (x – 7)/(2x + 1) (x \ne – 1/2)
    = (x + 3 – (x – 7))/(2x +1)
    = (x + 3 – x + 7)/(2x +1)
    = 10/(2x+1)
    2, (x -3)/(x^2-2x) + (2x – 5)/(x^2 + 4x + 4) (x \ne 0 ; x \ne \pm 2)
    = (x – 3)/(x(x-2) ) + (2x – 5)/( (x +2)^2)
    =( (x – 3)(x + 2)^2 + (2x – 5)x(x -2) )/( x(x – 2)(x +2)^2)
    = ( (x – 3)(x^2 + 4x +4) + (2x^2 – 5x)(x -2) )/( x(x – 2)(x + 2)^2)
    = ( x^3 + 4x^2 + 4x – 3x^2 – 12x – 12 + 2x^3 -4x^2 – 5x^2 + 10x)/( x(x -2)(x +2)^2)
    = (3x^3 – 8x^2 + 2x – 12)/( x(x -2)(x + 2)^2)
     

  2. Giải đáp + Lời giải và giải thích chi tiết:
    Bạn tham khảo~~
    1) (x + 3)/(2x + 1) – (x – 7)/(2x + 1)
    = (x + 3 – (x – 7)/(2x + 1)
    = (x + 3 – x + 7)/(2x + 1)
    = (10)/(2x + 1)
    _____________________________
    2) (x – 3)/(x^2 – 2x) + (2x – 5)/(x^2 + 4x + 4)
    = (x – 3)/(x(x – 2)) + (2x – 5)/((x + 2)^2)
    = (x – 3)/(x(x – 2)) + (2x – 5)/((x + 2)^2)        (MTC: x(x – 2)(x + 2)^2)
    = ((x – 3).(x + 2)^2)/(x(x – 2)(x + 2)^2) + ((2x – 5)(x – 2).x)/(x(x – 2)(x + 2)^2)
    = ((x – 3).(x^2 + 4x + 4))/(x(x – 2)(x + 2)^2) + ((2x – 5)(x^2 – 2x))/(x(x – 2)(x + 2)^2)
    = (x^3 +4x^2 + 4x -3x^2 – 12x – 12)/(x(x – 2)(x + 2)^2)+(2x^3-4x^2-5x^2 +10x)/(x (x – 2)(x +2)^2)
    = (x^3 +x^2 – 8x – 12)/(x(x – 2)(x + 2)^2) + (2x^3 – 9x^2 + 10x)/(x (x – 2)(x + 2)^2)
    = (x^3 + x^2 – 8x – 12 + 2x^3 – 9x^2 + 10x)/(x(x – 2)(x + 2)^2)
    = (3x^3 – 8x^2 + 2x – 12)/(x(x – 2)(x + 2)^2

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222-9+11+12:2*14+14 = ? ( )