Toán Lớp 7: ×/4=2y+1/3=×-2y-1/y (với y# 0)
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Toán Lớp 7: ×/4=2y+1/3=×-2y-1/y (với y# 0)
Comments ( 1 )
\dfrac{x}{4} = \dfrac{{2y + 1}}{3} = \dfrac{{x – 2y – 1}}{y}\\
= \dfrac{{x – 2y – 1 – \left( {x – 2y – 1} \right)}}{{4 – 3 – y}}\\
= \dfrac{0}{{1 – y}} = 0\\
\Leftrightarrow \left\{ \begin{array}{l}
x = 0\\
2y + 1 = 0\\
x – 2y – 1 = 0
\end{array} \right.\\
\Leftrightarrow \left\{ \begin{array}{l}
x = 0\\
y = – \dfrac{1}{2}
\end{array} \right.\\
Vậy\,x = 0;y = – \dfrac{1}{2}
\end{array}$