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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Bài 2: Tìm x  Z biết: a) –26 – 2 (x + 7) = – 56 b) (-270) : (2x – 5)2 + 70 = 40

Toán Lớp 6: Bài 2: Tìm x  Z biết:
a) –26 – 2 (x + 7) = – 56
b) (-270) : (2x – 5)2 + 70 = 40

Comments ( 2 )

  1. Lời giải chi tiết:
    a) -26-2(x+7)=-56
    =>2(x+7)=-26-(-56)
    =>2(x+7)=30
    =>x+7=30:2
    =>x+7=15
    =>x=15-7
    =>x=8
    Vậy x=8
    b) (-270):(2x-5)^2+70=40
    =>(-270):(2x-5)^2=40-70
    =>(-270):(2x-5)^2=-30
    =>(2x-5)^2=-270:(-30)
    =>(2x-5)^2=9
    =>\(\left[ \begin{array}{l}2x-5=3\\2x-5=-3\end{array} \right.\)
    =>\(\left[ \begin{array}{l}2x=8\\2x=2\end{array} \right.\)
    =>\(\left[ \begin{array}{l}x=4\\x=1\end{array} \right.\)
    Vậy x=4 hoặc x=1

  2. Bài 2:
    a, -26 – 2(x + 7) = -56
      2(x + 7) = -26 – (-56)
      2(x + 7) = -26 + 56
      2(x + 7) = 30
      x + 7 = 30 : 2
      x + 7 = 15
      x = 15 – 7  
      x = 8
    Vậy x = 8
    b, (-270) : (2x – 5)^2 + 70 = 40
      -270 : (2x – 5)^2 = 40 – 70
      -270 : (2x – 5)^2 = -30
      (2x – 5)^2 = -270 : (-30)
      (2x – 5)^2 = 9
      (2x – 5)^2 = 3^2 hoặc (2x – 5)^2 = (-3)^2
    Ta có:
    TH1:
    (2x – 5)^2 = 3^2
    2x – 5 = 3
    2x = 8
    x = 8 : 2
    x = 4
    TH2:
    (2x – 5)^2 = (-3)^2
    2x – 5 = -3
    2x = -3 + 5
    2x = 2
    x = 2 : 2
    x = 1
    Vậy x = 4 hoặc x = 1
     

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222-9+11+12:2*14+14 = ? ( )

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