Toán Lớp 6: a 3x + 13 = 19
b 25 – 16 :2 mũ 3
c 44 : ơ 100 – ( 4.5 mũ 2 – 2 mũ 5: 2 mũ 3(]
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Toán Lớp 6: a 3x + 13 = 19
b 25 – 16 :2 mũ 3
c 44 : ơ 100 – ( 4.5 mũ 2 – 2 mũ 5: 2 mũ 3(]
Comments ( 2 )
Giải đáp:
$a) 3x+13=19$
$⇒ 3x= 19-13$
$⇒ 3x=6$
$⇒ x= 6:3$
$ ⇒ x=2$
$Vậy$ $x=2$
$b) 25-16:2³$
$= 25-16:8$
$= 25-2$
$=23$
$c) 44:[100-(4.5^2-2^5:2³)]$
$= 44:[100-(4.25-4)]$
$= 44:(100-96)$
$= 44:4$
$=11$
a .3x + 13 = 19
3x = 19 – 13
x = 6 : 3
x = 2
b .25 – 16 : $2^{3}$
= 25 – 16 : 8
= 25 – 2
= 23
c .44 : [100 – ( 4.$5^{2}$ – $2^{5}$ : $2^{3}$ )]
=44 : [100 – ( 4.25 – $2^{2}$) ]
= 44 : (100 – 96 )
=44 : 4
= 11
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