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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Bài 1: tìm x E Z, sao cho: (x+3)^4=16 (3x-1)^5=32 37+3x=40 105-(135-7x):9=97 Mn giúp mik với

Toán Lớp 6: Bài 1: tìm x E Z, sao cho:
(x+3)^4=16
(3x-1)^5=32
37+3x=40
105-(135-7x):9=97
Mn giúp mik với

Comments ( 2 )

  1. ( x + 3 )^4 = 16
    ⇔ x + 3 = ± 2
    ⇔ \(\left[ \begin{array}{l}x+3=2\\x+3=-2\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}x=- 1\\x=-5\end{array} \right.\) 
    Vậy x = – 1 ; x = – 5
    ( 3x – 1 )^5 = 32
    ⇔ ( 3x – 1 )^5 = 2^5
    ⇔ 3x – 1 = 2
    ⇔ 3x = 2 + 1 
    ⇔ 3x = 3
    ⇔ x = 3 : 3
    ⇔ x = 1
    Vậy x = 1
    37 + 3x = 40
    ⇔ 3x = 40 – 37
    ⇔ 3x = 3
    ⇔ x = 3 : 3
    ⇔ x = 1
    Vậy x = 1
    105 – ( 135 – 7x ) : 9 = 97
    ⇔ – ( 135 – 7x ) : 9 = 97 – 105
    ⇔ – ( 135 – 7x ) : 9 = – 8
    ⇔ – 135 + 7x  = – 8 . 9
    ⇔ – 135 + 7x  = – 72
    ⇔ 7x = – 72 + 135
    ⇔ 7x = 63
    ⇔ x = 63 : 7
    ⇔ x = 9
    Vậy x = 9

  2. (x+3)^4=16
    (x+3)^4=2^4
    \text{TH 1 :}                        \text{TH 2 :}
    x+3=2                                 x+3=-2
    x=2-3                                  x=(-2)-3
    x=-1                                    x=-5
    ⇒ x ∈ { -1 ; -5 }
    (3x-1)^5=32
    (3x-1)^5=2^5
    3x-1=2
    3x=2+1
    3x=3
    x=3:3
    x=1
    \text{Vậy x = 1}
    37+3x=40
    3x=40-37
    3x=3
    x=3:3
    x=1
    \text{Vậy x = 1}
    105-(135-7x):9=97
    (135-7x):9=105-97
    (135-7x):9=8
    135-7x=8.9
    135-7x=72
    7x=135-72
    7x=63
    x=63:7
    x=9
    \text{Vậy x = 9}
    \text{@Jinz}
     

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222-9+11+12:2*14+14 = ? ( )

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