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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: $x^{3}$-6$x^{2}$ +12x-8=0 tìm x

Toán Lớp 8: $x^{3}$-6$x^{2}$ +12x-8=0
tìm x

Comments ( 2 )

  1. x^3 – 6x^2 + 12x – 8 = 0
    ⇔ ( x – 2 )^3 = 0
    ⇔ x – 2 = 0
    ⇔ x = 2
    Vậy x = 2

  2. $#Paow$
    x^3-6x^2+12-8=0
    (x-2)^3=0   -> HĐT số 7
    <=>x-2=0
    <=>x=2
    Vậy tìm được giá trị x=2
     

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222-9+11+12:2*14+14 = ? ( )

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