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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tổng S = 1 + 3 + 3^2 + 3^3 + … + 3^15

Toán Lớp 6: Tổng S = 1 + 3 + 3^2 + 3^3 + … + 3^15

Comments ( 2 )

  1. S=1+3+3^2+3^3+…+3^15
    3S=3+3^2+3^3+…+3^16
    3S-S=(3+3^2+3^3+…+3^16)-(1+3+3^2+3^3+…+3^15)
    2S=3^16-1
    S=(3^6-1):2
    vậy S=(3^6-1):2
     
    Lời giải và giải thích chi tiết:
     

  2. S = 1 + 3 + 3^2 + 3^3 + … + 3^15
    => 3S = 3 + 3^2 + 3^3 + 3^4 + … + 3^16
    => 3S – S = ( 3 + 3^2 + 3^3 + 3^4 + … + 3^16 ) – ( 1 + 3 + 3^2 + 3^3 + … + 3^15 )
    => 2S = 3^16 – 1
    => S = {3^16 – 1}/2
    Vậy S = {3^16 – 1}/2
    #dtkc
     

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222-9+11+12:2*14+14 = ? ( )

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